Take the 2-minute tour ×
Board & Card Games Stack Exchange is a question and answer site for people who like playing board games, designing board games or modifying the rules of existing board games. It's 100% free, no registration required.

In Android: Netrunner, Djinn is a program that reads:

Djinn can host up to 3 [Memory Units] of non-icebreaker programs.
The memory costs of hosted programs do not count against your memory limit.

Parasite is a (non-icebreaker) program that reads:

Install Parasite only on a rezzed piece of ice.
Host ice has -1 strength for each virus counter on Parasite and is trashed if its strength is 0 or less.

I'd like to play and install a Parasite such that it is hosted on an opponent's ICE (for it's main benefit of reducing that ICE's strength) AND hosted on Djinn (to reduce MU costs).

Is this legal? Can one card be "hosted" on two other cards at once?

share|improve this question
    
I don't see what a computer program has to do with board and card games. –  Tom Au Feb 25 '13 at 17:07
1  
@TomAu ? Android: Netrunner is a card game... –  Johno Feb 25 '13 at 17:15
    
@TomAu Designed by Richard Garfield. Definitely on-topic. Boardgamegeek link. –  ghoppe Feb 25 '13 at 17:18
    
@ghoppe: I guess it was my mistake. But that's the conclusion I came to when I saw the word "program." I thought it might be better for the RPG site. –  Tom Au Feb 25 '13 at 17:36
add comment

1 Answer

up vote 5 down vote accepted

No, a card can't be hosted on two different cards at the same time. From the Netrunner FAQ on Fantasy Flight's website:

Can the Runner install Parasite on a piece of ice but host it on Djinn?

No. A card or counter can only be hosted in one place at a time. Parasite has the restriction that it must be installed on a piece of ice, and therefore it cannot also be hosted by Djinn

share|improve this answer
add comment

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.