We ran into a friendly argument while playing cribbage today and we're stumped as to how to count this hand. How do you count 3 Sixes, 1 Seven and 1 Eight?
First of all, there's only one fifteen: the seven and the eight. That's two points. (Note that the sixes can't participate in 15s at all)
Next, there are three runs of three: each six in turn, the seven, and the eight. That's 3*3 = nine points.
Finally, there's the trio of sixes, worth six points (or equivalently, three pairs of sixes).
So the final score for the hand is 2+9+6 = 17 points.