Take the 2-minute tour ×
Board & Card Games Stack Exchange is a question and answer site for people who like playing board games, designing board games or modifying the rules of existing board games. It's 100% free, no registration required.

If both Sanguine Bond and Exquisite Blood are in play and target player loses any life, is the game over?

share|improve this question

3 Answers 3

up vote 7 down vote accepted

Either your opponent will have to lose life or you will have to gain life to start the process. Then, yes, unless someone does something to stop it, you'll enter a loop which will win you the game.

share|improve this answer
Note: If an opponent controls Platinum Angel or casts Angel's Grace, or you control Abyssal Persecutor, this will enter into a loop of mandatory actions which will end the game in a draw. If an opponent has hexproof or shroud for some reason (Witchbane Orb, True Believer, etc.), Sanguine Bond won't be able to target him or her and the loop will terminate. –  Brian S Nov 26 '13 at 16:55
Aye, those would be examples of the opponent having done something to change the outcome. There are others. –  ikegami Nov 26 '13 at 16:58

Actually, you will not win. According to the comprehensive rules on infinite loops, if a loop contains only mandatory effects, the game ends in a draw. Since the cards don't say may, they are mandatory. Sorry no game winning combo here.

share|improve this answer
They're just regular triggered abilities, so they use the stack. That means you'll check for state-based effects between each trigger. Losing the game due to running out of life is one such state-based effect. At that point, the game just ends; it doesn't matter if there's another trigger still on the stack now. –  Alex P Jan 5 '14 at 5:07
The general idea of the rules on infinite loops is that it's a draw if there's really no way at all for them to stop. The end of the game is a perfectly good way for a loop to end, as is a player deciding to do something that breaks the loop. It's when a mandatory loop does something that doesn't end the game that it's a problem. –  Jefromi Jan 5 '14 at 14:36
In short, players regularly get priority, so this loop doesn't contain only mandatory effects. –  ikegami Jan 6 '14 at 2:14
the loop DOES contain only mandatory actions. players still getting priority is not related. A more accurate explanation of the reason this is wrong, is if a player will win as a result of the loop being executed N times, it is therefore a non-infinite loop. the rule informing the answer above only applies if the loop cannot terminate regardless of how many times it is executed. if players get priority, they can (but do not have to) perform actions to interrupt the loop to stop the draw. But the game should still end in a draw if they regularly get priority but are unable to stop the loop. –  Patters Jan 6 '14 at 12:16
@Patters is correct. This is an infinite loop of mandatory actions... but barring something like Platinum Angel in play, it will end the game rather than resulting in a draw. –  Brian S Jan 6 '14 at 14:02

the combo one goes till the opponent is at 0 life it is not infinite. The life has to come from somewhere if no opponent has life/ they are at 0 life the the combo ends. And the hex proof/ platinum angel thing do stop the combo but not in a draw. The opponent will be at zero, just not dead.

share|improve this answer
-1; The only thing that ends the combo is one of the two enchantments leaving the battlefield, one of the triggers being removed from the stack (temporarily interrupting the combo), or the controlling player running out of targets (either by eliminating all opposing players, or all remaining opposing players having shroud/hexproof). Platinum Angel, Phyrexian Unlife, etc. results in a draw. –  Brian S Feb 13 '14 at 15:30
Players can lose life to go below zero. What they can't do is spend life to go below zero (so you can't, say, use Yawgmoth's Bargain to draw your entire deck even if you have Platinum Angel in play) –  Chad Miller Feb 13 '14 at 20:56

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.