Board & Card Games Stack Exchange is a question and answer site for people who like playing board games, designing board games or modifying the rules of existing board games. Join them; it only takes a minute:

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top

There are 71 (excluding starting tile) playing tiles available and this number seems not equally divided by 2,3,4 or even 5. According to the rule we have to finish all the tiles. Does this mean the player who starts first get the advantage of playing more tiles?

share|improve this question
You could just allow the first player to play the starting tile (and place a follower) to make it come out even if it's a big deal. – Jefromi Dec 30 '13 at 2:39
up vote 13 down vote accepted

Yes, depending on how many players there are and what expansions are being played, the game will sometimes end with one or more players having played one tile less.

Furthermore, some tiles can become discarded. At times, early on in the game, a four sided city tile has no where to go and thus has to be discarded; the player draws again, and upsets the tile distribution.

Another instance is when playing the Traders and Builders expansion. The builder allows players to draw up to two tiles per turn, and thus disturb tile distribution.

share|improve this answer

I have played in tournaments where you throw out one straight road tile before the starts. That way each player gets the same number of tiles.

share|improve this answer
70 is not divisible by 3 or 4. – hymie Feb 26 '14 at 16:09
The tournament is two player games, in my opinion as well as many carc players is Carcassonne plays best as a two player game. With only base set adding more players takes the skill out of the game and leaves luck of draw determining the winner instead of skill and strategy. Adding big expansions enables more players to play while retaining the balance of strategy vs. skill. – user6735 Feb 26 '14 at 17:16

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.