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This is a generalized version of @Guvante's answer. O (player 2) always wins in 4. The diagonals are not necessary to achieve a win. Examples are included in bold, but this strategy works for all choices made by X. X places a piece at (a,b): (1,1) O chooses a row that is not a, and places two pieces in that row, but not in column b: (2,2) and (2,5) Now, ...


I have flip-flopped a few times, but think that Player 2 has an unbeatable strategy. The trick is that Player 1 needs an X in each row and each column while Player 2 needs a "box". Four O's that form a rectangle with no X's that share a row or column with said rectangle. First two O's sharing a row with self and separated by 1 square. Never put below or ...

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