New answers tagged poker-texas-holdem
The best "hand" of five cards wins. That is two pair: KK QQ A kicker, and player B wins. Player A has a pair of fours that "doesn't play" because there are already two pairs on the board (and no room for a third pair in a five card hand). But player B's ace kicker does play (and beat's Player A's 4-kicker). Change the board to KKQ32, and Player A wins, ...
Player B wins. All that matters is the best 5 card hand you can make with the combined 7 cards. So player A does NOT have a pair of 4 as a kicker... player A has K,K,Q,Q,4. Player B has K,K,Q,Q,A. Both identical 2 pairs, but player B has A which beats 4.
To answer you title question: No. You are obliged to use 2 and only 2 of your hole cards. There are main 2 differences between Texas Hold'em and Omaha Hold'em. The number of hole cards you have. The number of hold cards you must use to create your final hand. In Texas Hold'em you get 2 hole cards dealt to you, but are not required to use any of them to ...
QQQ99 wins over QQ999, so Player 1 gets it. When comparing two full-houses, the higher triple wins; if both players have the same triple then the higher pair wins. If both players have the same triple and the same pair, then they split the pot.
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