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Jan
15
comment How to Measure Luck vs Skill in Games?
@tengfred Yep, I see! And if we change "same difference in skill" to "best player vs normal player", as you mention above, that does solve the issue. We could maybe instead look at players who beat each other 3/4 of the time (+200 skill), and measure the length of the longest chain of players (which for a large sample is effectively the width of the spread as mentioned above).
Jan
14
comment How to Measure Luck vs Skill in Games?
@tengfred Elo is based on a rating gap of +200 skill means that one player should win 3/4 of the time (of the non-drawn games), the lower rated player should win only 1/4.
Jan
14
comment Does a winning strategy exist for Don't Break the Ice?
This is great and should really be the selected answer. If the second player ensures the corner squares are removed within the first eight moves then the game must last an odd number of turns, and so the second player wins. As you say the second player may need to prioritise one corner over another to prevent the first player dropping it by disconnecting it.
Jan
9
comment How to Measure Luck vs Skill in Games?
+1 This sounds workable. Did you definitely mean -12 to +12? I was expecting something like -6 to +6.
Jan
8
comment How to Measure Luck vs Skill in Games?
You haven't defined what it means for a player to play with random actions. For example in poker it is important that a player's bids do not reveal their hand, and so they should bid 'randomly' using a carefully calculated distribution. Just because the best strategy is to play 'randomly' does not mean there is no skill in the game.
Jan
3
comment Identify a numbers game where you strike out numbers
You start with an odd number of digits and cross out digits in pairs. When you write out all the remaining digits do you then have to get rid of both sets of digits?
Dec
27
comment Can the pirate be placed on the edge of the board?
This is very interesting, thanks. Do you have links to images of older seafarers editions without frames?
Nov
10
comment I have the Alhambra base set only, in which order should I buy the expansions?
Thanks for this answer. Great level of detail!
Nov
8
comment What are the odds of getting the following hands in euchre?
@ghoppe Thanks! I don't think that's the issue, but it's an interesting anomaly. The python script definitely excludes scenario 1 from scenario 2. My guess is that my arithmetic is wrong somewhere in the calculation, but I haven't spotted where yet!
Nov
6
comment Remembering Decktet Card Distribution
+1 Thanks very much - these are good summaries. I found another image which may also be useful, which I'll post once I find it again!
Nov
5
comment What are the odds of getting the following hands in euchre?
@shujaa Thanks! I've made an edit to include that now.
Nov
2
comment Is team approval voting kept secret?
+1 Good answer. Just wanted to say that the spies win the game if there are 5 failed votes in a round.
Oct
26
comment Are some pieces better than others in Blokus?
I agree, the "one" is the best piece and so you shouldn't try to get rid of it
Oct
26
comment Are some pieces better than others in Blokus?
@JoeGolton I was actually trying not to ask which pieces to play first :-) I already asked that here: boardgames.stackexchange.com/questions/1497/…
Oct
25
comment What are the odds of getting the following hands in euchre?
Hi Firefeather. I've been reading through some of the older posts recently, and I don't think the calculations above are quite right. I think you're right that you can ignore ordering, but in that case the total number of hands isn't 24*23*22*21*20, it's that divided by 5*4*3*2*1 (or 24C5). Also I didn't follow the logic in scenario 2 when it came to looking at the four remaining cards.
Oct
5
comment What are the chances of losing Pandemic on the first turn?
@bwarner Jefromi - I agree - trying to stop the chain reactions would definitely be an improvement on the above strategies. I'll have a look at simulating it when I get a chance.
Aug
16
comment How likely are you to lose because Fool's Landing sinks into the abyss?
@user1873 Great! Let me know if you want any further bits broken down.
Aug
15
comment How likely are you to lose because Fool's Landing sinks into the abyss?
P(No sandbags | v=1) = P(No sandbags given v=1) = P(The one non-WR card is not a sandbags card) =(23-2n)/(25-2n)
Aug
15
comment How likely are you to lose because Fool's Landing sinks into the abyss?
Breaking it down: P(v=1) = (2 orderings)*(3 ways to pick a WR)*(25-2n ways to not pick a WR)/(total ways to pick two ordered cards) = 6(25-2n)/((28-2n)(27-2n))
Aug
10
comment How likely are you to lose because Fool's Landing sinks into the abyss?
@user1873 I ran a script and came up with the diver's chance of not being able to reach Fool's Landing as 4611612/18574248 which is about 25%. It's more than the explorer, but less than everyone else, so sounds about right. If anyone wants to either check my (horrific) code, or calculate it independently then let me know!