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Post Reopened by TheThirdMan, Malco, Toon Krijthe, Samthere, SocioMatt
attempted to reword the question to make it clearer, revert if you believe it changes intentions too much, seems to be just a failure to understand how the draw and discard steps work.
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In the quick reference paperquick reference paper they say - draw a hand of seven cards, then player who takes the first turn won't draw a card that turn.:

Shuffle your deck, then draw a hand of seven cards. The player who takes the first turn won’t draw a card that turn.

That means, both players will draw 7 cards, first player will start with 7, second player will draw a card, that is 8.

In the rules, they say - maximum number of cards is 7, player has to discard the exceeded number of cards in his clean up step.:

402.2. Each player has a maximum hand size, which is normally seven cards. A player may have any number of cards in his or her hand, but as part of his or her cleanup step, the player must discard excess cards down to the maximum hand size.

So, if the first player will playplays one card, what is the basic number of cards in the hand, will he draw 1 card next his roundturn to get atto maximum hand size (7) or will he draw a 2 cards, to get atto maximum hand size (7) plus one?

Because second player began the game with maximum hand size cards (7) plus 1 (the card he drew on his first turn).

Or will first player always draw cards to have 7 cards in a handSo, and second player will keep the advantage of having 8 cards in his draw step to the end of game?will the player who goes first always draw cards to have 7 cards in a hand, and the player who goes second will keep the advantage of having 8 cards in his draw step until the end of the game?

Or the maximum cards at the clean up step is 7 in the hand, but the base cards number (except first round for first player)will the maximum cards at the clean up step be 7 in the hand, but the number of cards in hand during the player's turn (except first turn for the player going first) is 8. That is 8, that meansto say both players have 7 cards inat the start of their draw step and draw one card (toto have 8)? It is little bit chaotic.

In the quick reference paper they say - draw a hand of seven cards, then player who takes the first turn won't draw a card that turn.

That means, both players will draw 7 cards, first player will start with 7, second player will draw a card, that is 8.

In rules, they say - maximum number of cards is 7, player has to discard the exceeded number of cards in his clean up step.

So, if the first player will play one card, what is the basic number of cards in the hand, will he draw 1 card next his round to get at maximum (7) or will he draw a 2 cards, to get at maximum (7) plus one?

Because second player began with maximum cards (7) plus 1.

Or will first player always draw cards to have 7 cards in a hand, and second player will keep the advantage of having 8 cards in his draw step to the end of game?

Or the maximum cards at the clean up step is 7 in the hand, but the base cards number (except first round for first player) is 8, that means players have 7 cards in their draw step and draw one card (to have 8)? It is little bit chaotic.

In the quick reference paper they say:

Shuffle your deck, then draw a hand of seven cards. The player who takes the first turn won’t draw a card that turn.

That means, both players will draw 7 cards, first player will start with 7, second player will draw a card, that is 8.

In the rules, they say :

402.2. Each player has a maximum hand size, which is normally seven cards. A player may have any number of cards in his or her hand, but as part of his or her cleanup step, the player must discard excess cards down to the maximum hand size.

So, if the first player plays one card, what is the number of cards in the hand, will he draw 1 card next turn to get to maximum hand size (7) or will he draw 2 cards, to get to maximum hand size (7) plus one?

Because second player began the game with maximum hand size cards (7) plus 1 (the card he drew on his first turn).

So, will the player who goes first always draw cards to have 7 cards in a hand, and the player who goes second will keep the advantage of having 8 cards in his draw step until the end of the game?

Or, will the maximum cards at the clean up step be 7 in the hand, but the number of cards in hand during the player's turn (except first turn for the player going first) is 8. That is to say both players have 7 cards at the start of their draw step and draw one card to have 8? It is little bit chaotic.

Post Closed as "Needs details or clarity" by David Z, Joe W, Nij, Ken Herbert, tsuma534
added 2 characters in body
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luky
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In the quick reference paper they say - draw a hand of seven cards, then player who takes the first turn won't draw a card that turn.

That means, both players will draw 7 cards, first player will start with 7, second player will draw a card, that is 8.

In rules, they say - maximum number of cards is 7, player has to discard the exceeded number of cards in his clean up step.

So, if the first player will play one card, what is the basic number of cards in the hand, will he draw 1 card next his round to get at maximum (7) or will he draw a 2 cards, to get at maximum (7) plus one?

Because second player began with maximum cards (7) plus 1.

Or will first player always draw cards to have 7 cards in a hand, and second player will keep the advantage of having 8 cards in his draw step to the end of game?

Or the maximum cards at the clean up step is 7 in the hand, but the base cards number (except first round for first player) is 8, that means players have 7 cards in their draw step aand draw one card (to have 8)? It is little bit chaotic.

In the quick reference paper they say - draw a hand of seven cards, then player who takes the first turn won't draw a card that turn.

That means, both players will draw 7 cards, first player will start with 7, second player will draw a card, that is 8.

In rules, they say - maximum number of cards is 7, player has to discard the exceeded number of cards in his clean up step.

So, if the first player will play one card, what is the basic number of cards in the hand, will he draw 1 card next his round to get at maximum (7) or will he draw a 2 cards, to get at maximum (7) plus one?

Because second player began with maximum cards (7) plus 1.

Or will first player always draw cards to have 7 cards in a hand, and second player will keep the advantage of having 8 cards in his draw step to the end of game?

Or the maximum cards at the clean up step is 7 in the hand, but the base cards number (except first round for first player) is 8, that means players have 7 cards in their draw step a draw one card (to have 8)? It is little bit chaotic.

In the quick reference paper they say - draw a hand of seven cards, then player who takes the first turn won't draw a card that turn.

That means, both players will draw 7 cards, first player will start with 7, second player will draw a card, that is 8.

In rules, they say - maximum number of cards is 7, player has to discard the exceeded number of cards in his clean up step.

So, if the first player will play one card, what is the basic number of cards in the hand, will he draw 1 card next his round to get at maximum (7) or will he draw a 2 cards, to get at maximum (7) plus one?

Because second player began with maximum cards (7) plus 1.

Or will first player always draw cards to have 7 cards in a hand, and second player will keep the advantage of having 8 cards in his draw step to the end of game?

Or the maximum cards at the clean up step is 7 in the hand, but the base cards number (except first round for first player) is 8, that means players have 7 cards in their draw step and draw one card (to have 8)? It is little bit chaotic.

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luky
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  • 1
  • 4

Magic the gathering number of cards in a hand

In the quick reference paper they say - draw a hand of seven cards, then player who takes the first turn won't draw a card that turn.

That means, both players will draw 7 cards, first player will start with 7, second player will draw a card, that is 8.

In rules, they say - maximum number of cards is 7, player has to discard the exceeded number of cards in his clean up step.

So, if the first player will play one card, what is the basic number of cards in the hand, will he draw 1 card next his round to get at maximum (7) or will he draw a 2 cards, to get at maximum (7) plus one?

Because second player began with maximum cards (7) plus 1.

Or will first player always draw cards to have 7 cards in a hand, and second player will keep the advantage of having 8 cards in his draw step to the end of game?

Or the maximum cards at the clean up step is 7 in the hand, but the base cards number (except first round for first player) is 8, that means players have 7 cards in their draw step a draw one card (to have 8)? It is little bit chaotic.