Timeline for Is it possible in UNO to run out of cards to draw?
Current License: CC BY-SA 4.0
11 events
| when toggle format | what | by | license | comment | |
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| Feb 5, 2020 at 21:05 | history | edited | Brilliand | CC BY-SA 4.0 |
Account for players being able to play what they just drew
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| Feb 5, 2020 at 20:22 | comment | added | Brilliand | @IvoBeckers Crap, I forgot that rule. Hmm, I think there's enough flexibility there to work around it... I'll edit it again. | |
| Feb 5, 2020 at 10:09 | comment | added | Ivo | in your example you don't always play when you can. Like when a player draws a wild draw 4 he is allowed to play it immediately, but you don't do that. Not sure if this goes against the OP's "no self-destruction" rule | |
| Feb 5, 2020 at 0:20 | history | edited | Brilliand | CC BY-SA 4.0 |
Replaced the procedure with a right one instead of a wrong one
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| Feb 4, 2020 at 23:38 | comment | added | Brilliand | @mmathis Actually yeah, I've found it does work out that way with 5 lucky players; but 2 lucky players (that never miss a play) are able to suppress the other 8 no problem. I'll update the answer accordingly, with an example decklist. | |
| Jan 29, 2020 at 20:51 | comment | added | mmathis | I mean there aren't enough cards to set up the scenario which prevents players from playing, ergo the players can play and the draw/discard piles aren't run dry | |
| Jan 29, 2020 at 20:48 | comment | added | Brilliand | @mmathis Not having enough cards in the deck is the whole point. | |
| Jan 29, 2020 at 17:05 | vote | accept | Philipp | ||
| Jan 29, 2020 at 1:33 | comment | added | mmathis | While this may result in the scenario the OP described (and I have doubts that it would, since the discard pile would be shuffled as needed to allow the +4s to be resolved), I don't think there are enough cards in the deck to actually make this happen. | |
| Jan 28, 2020 at 1:04 | history | edited | Brilliand | CC BY-SA 4.0 |
Added tl;dr answer at top
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| Jan 27, 2020 at 22:57 | history | answered | Brilliand | CC BY-SA 4.0 |