3

Do to the deterministic nature of the game, if I have a decent memory I can easily know what cards are left in my deck, if not their order. I have two cards in my hand that let me draw a card (1 each) and I know there are 4 cards left in my deck, two of which will also let me draw a card. What are the chances I'll be able to draw my entire remaining deck?

Improve this question
2
  • This is a fairly simple probability problem... if I knew the rules of Star Realms. What are the card drawing rules?
    – Philip Kendall
    Nov 10, 2016 at 19:00
  • Some cards will allow you to draw a card under certain conditions, for this question, you can take it as read that the condition is filled. Simply, you an draw 2 of the 4 cards remaining, and if any of the drawn cards let you draw a card you can continue to do so.
    – aslum
    Nov 10, 2016 at 19:07

1 Answer 1

Reset to default
8

50%

Symbolizing the cards that give you a draw a D, and the cards that do not as N, there are 6 possible permutations of draw vs no-draw.

In each permutation, the second N card represents the farthest you can get through your deck on this turn. I have bolded it for easier visibility.

DDNN

DNDN

DNND

NDDN

NDND

NNDD

Improve this answer
1
  • 4
    This could also be explained by defining any permutation that ends with a Draw card last as the fail condition.
    – Drunk Cynic
    Nov 12, 2016 at 2:03

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .