# Can a phase requiring two colored sets be completed with the same color?

In Phase 10 can a phase requiring collecting x of one color and y of one color be completed using x+y of the same color?

E.G. Can Candy Castle / Mountain Vista Phase 7 (4 of one color + 6 of one color) or Phase 8 (5 of one color + 5 of one color) be completed with 10 of the same color?

or

Can Cocoa Canyon Phase 3 (4 cards of one color + 5 cards of one color) be completed with 9 card of the same color?

• which version of phase 10 has a set of 5 of a color and set of 4 of a color? Some quick searching is not showing this combo – Joe W Jun 22 '19 at 23:56
• Canyon phase I think – Louis Reuther Jun 23 '19 at 11:02
• Looks like it's phase 3 of the "Cocoa Canyon" version, according to Wikipedia. – Benjamin Cosman Jun 23 '19 at 14:29
• I would assume it would follow that the same rules as if you can use 1 number for both set in any of the phases. If you would allow some one with 6 of one number to go down on the first phase (2 set of 3) in the regular game then I would allow this. – Styxsksu Jun 24 '19 at 13:52
• As an aside, the odds of this situation coming up in an actual game are so slim that it almost makes this a moot point. Ignoring wilds and skips, the probability of getting dealt a hand you can make phase with on the first turn using two different colors for candy castle phase 7 is about \$0.00076\$ while making phase on the first turn with only one color is about \$0.00000017\$, more than a thousand times less likely. In terms of actual play, the obviously superior strategy is to collect two colors unless you happened to have been dealt nine of a single color. – JMoravitz Jun 26 '19 at 12:06