Three players are all in, and two tie for the win. Does the loser pay both players the full amount of their chips bet?
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It would help if you could add how much each had before they went all in.– Joe WJul 19, 2019 at 0:35
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1 Answer
The answer will depend on who has the most chips. Let's assume that there are 3 players, A, B and C.
A has 100 chips, B has 50 chips, and C has 10 chips. All three go all-in. There will be two pots.
The first pot, called the "Main Pot", will have 30 chips in it, 10 chips each from A, B, and C (the value of C's all-in). A, B, and C are eligible to win this pot.
The second pot, call the "Side Pot", will have 80 chips in it, 40 from B and 40 from A, the value of B's all-in. Only A and B are eligible to win this pot.
A still has 50 chips on the table that is not in a pot.
If C loses:
- A and B split all of the chips in both pots evenly.
- C is eliminated. A has 105 chips. B has 55 chips.
If B loses:
- A wins the 80 chip pot, A and C split the 30 chip pot.
- B is eliminated. A has 145 chips. C has 15 chips.
If A loses:
- B wins the 80 chip pot, B and C split the 30 chip pot.
- A has 50 chips. B has 95 chips. C has 15 chips.
