When playing Attack
, the turns of the current player are transferred to the next player, and a fixed number of turns are added. However, this seems to be inconsistent with the official text:
ATTACK 2X 4 CARDS
Do not draw any cards. Instead, immediately force the next player to take 2 turns in a row. Play then continues from that player. The victim of this card takes a turn as normal (pass-or-play then draw). Then, when their first turn is over, it's their turn again.
If the victim of an Attack Card plays an Attack Card on any of their turns, the new target must take any remaining turns plus the number of attacks on the Attack Card just played (e.g. 4 turns, then 6, and so on).
The text suggests that this would be the effect:
- P1 plays
Attack
, so P2 has 2 turns. - P2 plays
Attack
, so P3 has 4 turns. - P3 plays
Attack
, so P4 has 6 turns. (Pn
refers to P(n mod p)
forp
players.) - P4 plays
Attack
, so P5 has 8 turns. - P5 plays
Five Different Cards
(to getAttack
) and drawsShuffle
, with 7 turns left. - P5 plays
Attack
, so P6 has 9 turns.
The inconsistency is that P1 already has 1 turn when playing Attack, which would imply adding 1 turn per Attack card:
- P1 plays
Attack
, so P2 has 1+1=2 turns. - P2 plays
Attack
, so P3 has 2+1=3 turns. - P3 plays
Attack
, so P4 has 3+1=4 turns. - P4 plays
Attack
, so P5 has 4+1=5 turns. - P5 plays
Five Different Cards
(to getAttack
) and drawsShuffle
, with 4 turns left. - P5 plays
Attack
, so P6 has 4+1=5 turns.
This is clearly not what the text suggests, which is that 2 turns should be added. But even with that change, it seems like 1 extra turn should be added to everything:
- P1 plays
Attack
, so P2 has 1+2=3 turns. - P2 plays
Attack
, so P3 has 3+2=5 turns. - P3 plays
Attack
, so P4 has 5+2=7 turns. - P4 plays
Attack
, so P5 has 7+2=9 turns. - P5 plays
Five Different Cards
(to getAttack
) and drawsShuffle
, with 8 turns left. - P5 plays
Attack
, so P6 has 8+2=10 turns.
Is the inconsistency a result of misinterpreting the description, or is it just that the Attack
card has a special extra effect of subtracting 1 turn when the turn count is 1 before adding (3 after adding)?
Transfer turns to the next player, add 2 turns, and subtract 1 turn if the turn count is 3.
I say that it seems inconsistent because in this example, P3 can have 2 extra turns from a 1 turn count difference:
- P1 plays
Attack
, so P2 has 2+2-1=2 turns. - P2 plays
Shuffle
and drawsShuffle
, with 1 turn left. - P2 plays
Attack
, so P3 has 1+2-1=2 turns. (P3 has 2+2=4 turns if the previous line is deleted.)
Or would P3 get 3 turns (4 if the second line is deleted) in this case, corresponding to the following effect?
Transfer turns to the next player and add 2 turns. The turn count is normally 0, and players still take 1 turn if the turn count is 0.
This last rule avoids removing 2 turns from using 1, but it means 1 original turn and 1 Attack
turn left are different states (but only when using Attack
).
Attack
, P2 uses 1 turn, P2 playsAttack
. Should P3 have 2 or 3 turns? Is it significant that P2 had 1 turn left as anAttack
victim (3 turns), or is it no different from having 1 original turn (2 turns)? If it's 2, then does it seem correct that P3 loses 2 turns because P2 used 1 turn?