If white tenukis thrice after the 3-3 invasion, and answers Q18 with R18, then white kills with S19:
But what if white plays Q19 instead?
Can black still kill unconditionally, or ko is the best one can achieve?
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Sign up to join this communityI know this is a textbook situation, but I do not practice tsumego, so I had to read through this. It was quite tricky and took some time to, hopefully, get right.
The strongest (i.e. hardest to correctly answer) resistance I found is this:
$$ ------------------
$$ . X 3 5 2 . . . |
$$ . X O O 1 . 4 . |
$$ . X X X O O O . |
$$ . . . . X X O . |
$$ . . . . . . X . |
$$ . . . . . X . . |
After 5, white has nothing left.
I'll grant you that looks strange, so let's see why other moves are worse.
$$ ------------------
$$ . X 3 . 2 . 5 . |
$$ . X O O 1 4 . . |
$$ . X X X O O O . |
$$ . . . . X X O . |
$$ . . . . . . X . |
$$ . . . . . X . . |
If 4 captures, black kills with 5.
$$ ------------------
$$ . X X a O b 1 . |
$$ . X O O . O . c |
$$ . X X X O O O . |
$$ . . . . X X O d |
$$ . . . . . . X . |
$$ . . . . . X . . |
a and b are miai, and c and d, too - if white takes or prevents one, black always takes the other.
$$ ------------------
$$ . X X 3 O . 1 . |
$$ . X O O . O 2 5 |
$$ . X X X O O O . |
$$ . . . . X X O 4 |
$$ . . . . . . X . |
$$ . . . . . X . . |
White's strongest attempt is probably trying to trick black into mistakenly not playing at 3. If black replies correctly, it leads to temporary seki. White cannot play inside without creating a dead shape, and black cannot capture white directly.
However, at the end of the game this shape is dead: It is "reducible to bent-4 in the corner". Situations like this are actually quite complicated and even lead to arguments at the highest level of professional play.
$$ ------------------
$$ . X 3 . 2 . 4 . |
$$ . X O O 1 5 . a |
$$ . X X X O O O . |
$$ . . . . X X O . |
$$ . . . . . . X . |
$$ . . . . . X . . |
If 4 at 2-1, then black 5 kills. If white 4 at the other 1-2 point, black 5 kills, too.
$$ ------------------
$$ . X . . 2 . 3 . |
$$ . X O O 1 . 4 . |
$$ . X X X O O O . |
$$ . . . . X X O . |
$$ . . . . . . X . |
$$ . . . . . X . . |
If black plays 3 here, as I was initially sure is the answer, it is in fact a mistake and white punishes with 4. Black's strongest attempt is easily foiled:
$$ ------------------
$$ . X 1 . O 2 X 4 |
$$ . X O O X . O . |
$$ . X X X O O O . |
$$ . . . . X X O 3 |
$$ . . . . . . X . |
$$ . . . . . X . . |
White 2 is important. If white instead captures, she dies:
$$ ------------------
$$ . X 1 3 O . X . |
$$ . X O O X 2 O 5 |
$$ . X X X O O O . |
$$ . . . . X X O 4 |
$$ . . . . . . X . |
$$ . . . . . X . . |
This shape is the same seen earlier.
To sum it up: White's other atari is the same result.
The black stone at Q18 is in a ladder, albeit a short one. If black pushes this, with R18, black will eventually be killed and white will live. R18 is a strong KO-threat, however, because if it is not answered black can kill the white group.
If black plays P29 white must capture at R18. If black pushes at O19 the capture is again forced and white will eventually have to connect at Q18. losing 1-2 points of potential territory. This also is a significant ko-threat for black, although not as large as R18.