# Tag Info

26

Your opponent won the pot. The fact that there's a flush on the table isn't relevant to whether or not your pocket cards matter. Each player creates the best 5-card hand that he can out of the total 7 cards (2 pocket cards plus 5 table cards). While it is possible that the best 5-card hand is the 5 table cards, that is not the case here. The best 5-card ...

25

If a player cannot cover a blind, that player is all-in and the bets are handled just as if that player had gone all-in on an ordinary bet. The main pot gets an amount of money from each player who bets equal to the all-in player's stake. Any further betting goes into a side pot, which the all-in player is ineligible to win.

25

Yes, it is a split pot. Both players have AAKK8. You always make your best 5 card hand from the cards available. From Wikipedia: A hand always consists of five cards. In games where more than five cards are available to each player, the best five-card combination of those cards must be played. Any cards not included in the hand do not affect its ranking. ...

25

Suppose the five community cards wind up being 9♦, 10♥, 10♣, J♠, and 3♠. Then C would win with a better full house than A, but A's full house is better than B's pair of 10's. Before C folds, this would count towards his 25% win chance; after he folds it counts for A's 56%. When C folds, we're essentially taking his 25% chance to win, and splitting it up ...

24

Player B wins. All that matters is the best 5 card hand you can make with the combined 7 cards. So player A does NOT have a pair of 4 as a kicker... player A has K,K,Q,Q,4. Player B has K,K,Q,Q,A. Both identical 2 pairs, but player B has A which beats 4.

23

QQQ99 wins over QQ999, so Player 1 gets it. When comparing two full-houses, the higher triple wins; if both players have the same triple then the higher pair wins. If both players have the same triple and the same pair, then they split the pot. Note that all suits are equal in Poker - the ranking of suits from games such as Bridge and Five Hundred have no ...

15

The answer will depend on who has the most chips. Let's assume that there are 3 players, A, B and C. A has 100 chips, B has 50 chips, and C has 10 chips. All three go all-in. There will be two pots. The first pot, called the "Main Pot", will have 30 chips in it, 10 chips each from A, B, and C (the value of C's all-in). A, B, and C are eligible to win ...

14

You each make the best 5 card hand you can. You have QQQJ9, your opponent has QQQA9 which is a higher hand, and so your opponent wins.

14

While I don't have the exact math to prove it, it certainly seems reasonable. The question to ask is, in the 25% of cases where C would've won, who would've had the second best hand? If the answer is almost always A, then you'll get the results you saw. Here the thing that really boosts A's chance are having a 9 on the table. But when C is in play, that ...

13

No, the pair of 3s doesn't matter. You can't make 3 pairs with 5 cards. Bob makes K,K,Q,Q,10. Charlie makes K,K,Q,Q,3. Bob takes the hand.

13

Certainly. Player 1 : 5h 6h Player 2 : 8c 9c Community cards: 7h 8h 9h 8d 9d Player one has 5h 6h 7h 8h 9h Player two has 8c 8h 9c 9h 9d

11

It's a split. If you take the highest scoring set of five cards, each player is holding a double king, queen, ten and nine. The eight of clubs and four of hearts are never considered in scoring. Here's an explanation of this five-card scoring rule. Especially: Five might be the most important number in poker, if only because five cards make a complete ...

10

Because Player 1 made the final raise, he should be the first to show his cards when players reach the showdown. However, according to the World Series Of Poker rules, When a player holds a hand that is likely the winner, they should show that hand immediately to speed play. In this case, it appears Player 2, in an effort to speed up play, short-cutted ...

9

Player B is considered all in and Player C must still match the full blind amount and there will just be two possible winning piles depending on who wins. If Player B wins they would win 60 chips per player that paid the big blind and the next high hand would win the rest. pokerlistings.com When a player's stack is less than the amount of the small blind, ...

9

The flop eliminates a majority of reasonable players because they have such a low probability of winning anything. With a dripfed board, they would stay for longer and commit more, thereby being priced in despite having no real chance. It avoids early big bets by high pocket pairs and (suited) connectors that have caught something from the first single card ...

9

The problem is that a straight cannot be made with an Ace in the middle of the straight. Ace can be considered either the lowest card (forming a straight with A, 2, 3, 4, 5); or the highest card (forming a straight with 10, J, Q, K, A). It cannot be both low and high at the same time; so J, Q, K, A, 2 is not a straight. In the case of this hand, player 1's ...

7

When there are only two players left, player 2 showing his hand hurts him and no one else. Thus you can just ask him to make an official move (i.e. actually call), and then proceed with the game. This would work even if the previous bid wasn't All In - player 1 could continue playing with full knowledge of player 2's hand, and player 2 has only himself to ...

7

Yes there is a standard for notating poker games, though it's not so widely used. One of the reasons for this is doing it as a player in game is cheating, writing down the cards that have come out would be counting cards. The card values are: 2-9,T,J,Q,K,A in standard notation. Suits can be noted, with the symbol of the suit (♠♣♥♦) or the first letter of ...

6

The best "hand" of five cards wins. That is two pair: KK QQ A kicker, and player B wins. Player A has a pair of fours that "doesn't play" because there are already two pairs on the board (and no room for a third pair in a five card hand). But player B's ace kicker does play (and beat's Player A's 4-kicker). Change the board to KKQ32, and Player A wins, ...

6

The higher flush wins the pot. And a Q-J-10-8-6 is better than a Q-J-8-7-6 so your opponent won the pot. It's the same for any other non-flush hand where the highest cards form the tie break. Then you compare the next one and the next until 5 cards are in both hands. Then if both 5 card hands are identical it's a tie. In this case, your 3rd best card ...

6

In other words, do you choose how to play your hand in the end, or is the most valuable combination of cards automatically and involuntarily chosen? What a player claims to have, is irrelevant. The one and only thing that matters in deciding a player's hand is what cards that player may use. The one and only claim of a hand that matters is putting the cards ...

6

You get the highest possible five card combination. The remaining hole cards are lower than the A and K on the table -- best five cards then is Three of a Kind in 10s, Ace, King. Other cards are ignored, so both players have the same hand.

5

In Texas Hold'Em you use the strongest five-card hand that can be made using your two in-hand cards and the 5 board cards. The two cards that you do not use are ignored completely and have no effect on the hand rankings. (This is similar to 7-card stud and other 7-card variants) In the example you present, it sounds like each player has an identically-...

5

The best hand in either case would be two-pair with 8 as a kicker (A-A-K-K-8); it makes no difference if the 8 came from the table or from the hole cards. Since suit also doesn't matter, the hands would tie. So yes, it would be a split pot.

5

The reason for the difference is tied to concept of blinds, which are simply mandatory initial bets to ensure there is some money at play for every hand. In regular rounds (of three or more players), the small blind (one seat to the left of the button/dealer) is effectively the first bet (the small blind amount) and the big blind (two seats to the left of ...

5

Texas Hold'em counts the best five cards out of the community cards and your hand, which means the both of you have this result: A A J J 10 (Two Pair, Kicker 10) Because both of your hands are equally ranked, this will result in a Split Pot. There are no symbol weights like in other games, where Spades are worth more or less than Diamonds, and never will ...

5

While we can´t read minds, in this game player 1 wins because the best hand either player can make is two pair with Jacks and 8s (all from the community), so winner gets decided by the remaining high card. And player 1's Ace is higher than player 2's Queen. Player 2 having 2 pair doesn't help him win; Player 1 also has 2 pair by using only the community ...

4

You and your opponent both have "trip" queens. Then the side cards, or kickers, decide the issue. Your opponent has a side ace, and you have a side jack, both of which are higher than the nine on the board. So the ace plays. So does your jack, but aces "outkick" jacks. That is, you have QQQJ9, and your opponent has QQQA9 for a better hand. If your opponent'...

4

To answer you title question: No. You are obliged to use 2 and only 2 of your hole cards. There are main 2 differences between Texas Hold'em and Omaha Hold'em. The number of hole cards you have. The number of hold cards you must use to create your final hand. In Texas Hold'em you get 2 hole cards dealt to you, but are not required to use any of them to ...

4

In Texas Hold'em you construct the best 5 card hand you can out of the 7 cards available. The cards not included in the hand have no bearing on the winning or losing of any individual. For the scenario you described, if both players have straights and that are made up of the same set of cards and neither has a straight flush, then it is a tie and the pot is ...

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