Timeline for How to use big fun 'play the lottery' card
Current License: CC BY-SA 4.0
17 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
Apr 2, 2021 at 15:24 | comment | added | Darrel Hoffman | @ilkkachu Yeah, that's another weakness in design. I'd modify it to have a minimum bet as well. Maybe $10? Otherwise the card could just do nothing and be pointless. I feel like every card should be required to have some effect regardless of circumstances. | |
Apr 2, 2021 at 15:05 | comment | added | ilkkachu | @DarrelHoffman, I don't see why you couldn't bet $0. | |
Apr 1, 2021 at 18:12 | comment | added | Darrel Hoffman | @xLeitix Yeah, I'd redesign that to either just use 1d6 and halve the payout, or alternatively use 1d12, but Monopoly sets don't usually come with a d12, so you'd have to supply your own. Anything using 2+ dice is going to make it pointless to bet on anything other than the most likely outcome. It does seem as though gambling isn't an option though - when you draw this card, you must gamble, your only choice is how much you want to put on the line. | |
Apr 1, 2021 at 15:00 | comment | added | Acccumulation | @xLeitix Just because the expected value of the money is positive doesn't mean that the expected value of the utility is positive. If losing means that you won't be able to afford rent if you land on an opponent's space next turn, you probably shouldn't gamble. | |
Apr 1, 2021 at 9:51 | comment | added | xLeitix | @Joshua (that said, it's still not good design any way you turn it because the optimal strategy clearly becomes "always gamble when you can", not much tension in that decision) | |
Apr 1, 2021 at 9:49 | comment | added | xLeitix | @Joshua I think it's ok / normal that an event that you an only use a specific times (when you draw this card?) has a positive EV - otherwise, what would be the point of using this option if it has neutral or negative EV? What I am more concerned is that it seems like the game designer does not understand that not all numbers are equally likely with 2 D6 rolls ... or it's a gotcha by design, which I think would be even worse from a game design perspective. | |
Apr 1, 2021 at 3:03 | comment | added | Joshua | Is this supposed to be broken? Bet money for 16% chance of 10x payoff; e becomes 1.16. | |
Mar 31, 2021 at 21:00 | history | tweeted | twitter.com/StackBoardGames/status/1377365096427446274 | ||
Mar 31, 2021 at 16:38 | comment | added | ilkkachu | @DarrelHoffman, doh, indeed, the only choice is how much you can risk for the bet. I somehow managed to read it as "collect that many times the amount you placed". I've seen a similar one in some other game where it was "choose N, get N times some stuff if you roll >= N", which seems to make more sense in allowing you to go big or safe. | |
Mar 31, 2021 at 14:35 | comment | added | Darrel Hoffman | @ilkkachu Actually, it looks like the number you choose has no effect on the payout. If you place $50 and roll your number, you get $500 back, regardless of what that number was. So there's no good reason to choose any number other than exactly 7, which is the most common roll on 2d6. Sure, you could say and roll 12 and get really lucky, but the payout is the same, so why wouldn't you pick the most likely outcome? | |
Mar 31, 2021 at 12:24 | history | became hot network question | |||
Mar 31, 2021 at 11:54 | history | edited | L. Scott Johnson | CC BY-SA 4.0 |
added 242 characters in body
|
Mar 31, 2021 at 10:25 | answer | added | L. Scott Johnson | timeline score: 6 | |
Mar 31, 2021 at 8:40 | answer | added | robyaw | timeline score: 14 | |
Mar 31, 2021 at 8:24 | history | edited | StartPlayer | CC BY-SA 4.0 |
changed 'd1' and 'd2' to first and second so its doesn't read like a 1 and 2 sided die
|
Mar 31, 2021 at 4:26 | review | First posts | |||
Mar 31, 2021 at 6:04 | |||||
Mar 31, 2021 at 4:24 | history | asked | Megan Collins | CC BY-SA 4.0 |