In Betrayal at Baldur's Gate:
- The number of dice in a Haunt Roll is equal to the number of omens revealed.
- The Haunt is triggered by a Haunt Roll being 6 or higher (thus, successive omens are more likely to trigger the Haunt).
- The dice sides are 0,0,1,1,2,2.
- There are only 13 omens, so only 13 Haunt Rolls can happen throughout the game.
This means it's theoretically possible to go through all 13 omens without ever triggering the Haunt. This is different from Betrayal at a House on a Hill, where slight differences guarantee the Haunt.
My question is, what happens in that case? You've revealed all 13 omens, and rolled 5 of under each time, is there a rule for that eventuality?