Answers to a question on this hand suggested that one pass a bid of one diamond with 14 high card points because of 1) the three cards in the opposing suit, and 2) the "stranded" queen in that suit that reduces its value on offense.
Suppose, instead, (with equal vulnerability at matchpoints) over an opening bid of one diamond, you held (s) AQxx (h)Axx (d) xxx (c) Axx?* That is you still have three cards in the opposing suit, but no "stranded" honor. Would it now be ok to double for takeout, or is it still a pass?
Alternate example. Suppose you have Axxx (h)Axxx (d) Qx (c) Axx? Same 14 points, two cards in opponents' suit, but "stranded" Q. Would you be more, less, or about equally likely to double rather than pass compared to the other example?
*With AQx (h)Axx (d) Txxx (c) Axx, I would be tempted to call 1NT since the three aces are worth more than 12, and the value of my hand is more like 15, counting the diamond T. If partner holds any heartdiamond honor, or xx, the opposing suit may be "stopped" at four tricks.
